English
(n - k) · (n - k + 1)^{\overline{k}} = (n - k)^{\overline{k+1}}.
Русский
(n - k) · (n - k + 1)^{\overline{k}} = (n - k)^{\overline{k+1}}.
LaTeX
$$$$\forall n,k \in \mathbb{N},\ (n-k) \cdot (n-k+1)^{\overline{k}} = (n-k)^{\overline{k+1}}$$$$
Lean4
theorem ascFactorial_lt_pow_add (n : ℕ) : ∀ {k : ℕ}, 2 ≤ k → (n + 1).ascFactorial k < (n + k) ^ k
| 0 => by rintro ⟨⟩
| 1 => by intro; contradiction
| k + 2 => fun _ =>
by
rw [Nat.pow_succ, Nat.mul_comm, ascFactorial_succ, succ_add_eq_add_succ n (k + 1)]
exact
Nat.mul_lt_mul_of_le_of_lt (le_refl _)
(Nat.lt_of_le_of_lt (ascFactorial_le_pow_add n _) (Nat.pow_lt_pow_left (Nat.lt_succ_self _) k.succ_ne_zero))
(succ_pos _)