English
For all n,k, the prime factors of n^(k+1) are exactly the prime factors of n.
Русский
Для любых n и k простые делители n^(k+1) совпадают с простыми делителями n.
LaTeX
$$$ (n^{k+1}).primeFactors = n.primeFactors $$$
Lean4
theorem primeFactors_pow_succ (n k : ℕ) : (n ^ (k + 1)).primeFactors = n.primeFactors :=
by
rcases eq_or_ne n 0 with (rfl | hn)
· simp
induction k with
| zero => simp
| succ k ih => rw [pow_succ', primeFactors_mul hn (pow_ne_zero _ hn), ih, Finset.union_idempotent]