English
For all m,n, the natural-number less-than comparison agrees with the Num order: (m:ℕ) < n iff m < n.
Русский
Для любых m,n: сравнение меньше-числа по натуральным чисам совпадает с порядком Num: (m:ℕ) < n ⇔ m < n.
LaTeX
$$$\\forall {m,n : Num}, (m : \\mathbb{N}) < n \\Leftrightarrow m < n$$$
Lean4
@[norm_cast]
theorem lt_to_nat {m n : Num} : (m : ℕ) < n ↔ m < n :=
show (m : ℕ) < n ↔ cmp m n = Ordering.lt from
match cmp m n, cmp_to_nat m n with
| Ordering.lt, h => by simp [h]
| Ordering.eq, h => by simp [h]
| Ordering.gt, h => by simp [not_lt_of_gt h]