English
Let α be a division ring. For every integer n, the image of n^{-1} in ℚ cast to α equals the inverse of n cast to α.
Русский
Пусть α — кольцо деления. Для любого целого n образ n^{-1} из ℚ, приведённый в α, равен обратному образу n в α.
LaTeX
$$$ ∀ \alpha [\mathrm{DivisionRing}\,\alpha], ∀ n : \mathbb{Z}, \left( (n^{-1} : \mathbb{Q}) : \alpha \right) = (n : \alpha)^{-1}. $$$
Lean4
@[simp]
theorem cast_inv_int (n : ℤ) : ((n⁻¹ : ℚ) : α) = (n : α)⁻¹ :=
by
rcases n with n | n
· simp [cast_inv_nat]
· simp only [Int.cast_negSucc, cast_neg, inv_neg, cast_inv_nat]