English
For a family of predicates P_i on α indexed by i, the union over i of the sets {x ∈ α | P_i(x)} equals the set {x ∈ α | ∃ i, P_i(x)}.
Русский
Пусть P_i — семейство предикатов на α. Тогда ⋃_i { x ∈ α | P_i(x) } = { x ∈ α | ∃ i, P_i(x) }.
LaTeX
$$$$ \\bigcup_{i} \\{ x \\in \\alpha \\mid P_i(x) \\} = \\{ x \\in \\alpha \\mid \\exists i,\\ P_i(x) \\} $$$$
Lean4
theorem iUnion_setOf (P : ι → α → Prop) : ⋃ i, {x : α | P i x} = {x : α | ∃ i, P i x} :=
by
ext
exact mem_iUnion