English
Let S ⊆ E and f: E →ₐ[F] E' be an F-algebra homomorphism. Then the image of the adjoin of S under f equals the adjoin of the image of S: map f (adjoin F S) = adjoin F (f'' S).
Русский
Пусть S ⊆ E и f: E →ₐ[F] E' — гомоморфизм алгебр над F. Тогда образ адъюнта S равен адъюнту образа S: map f (adjoin F S) = adjoin F (f '' S).
LaTeX
$$$(\\\\operatorname{adjoin}_F S).\\\\map f = \\\\operatorname{adjoin}_F (f '' S).$$$
Lean4
theorem adjoin_map {E' : Type*} [Field E'] [Algebra F E'] (f : E →ₐ[F] E') : (adjoin F S).map f = adjoin F (f '' S) :=
le_antisymm (map_le_iff_le_comap.mpr <| adjoin_le_iff.mpr fun x hx ↦ subset_adjoin _ _ ⟨x, hx, rfl⟩)
(adjoin_le_iff.mpr <| Set.monotone_image <| subset_adjoin _ _)