instIsAlgClosureAlgebraicClosureSubtypeMemOfIsAlgebraic

English

For a given K,L with L algebraic over K, IsAlgClosure K (AlgebraicClosure (Subtype mem E)) holds for suitable E.

Русский

Для данного K,L с L алгебраическое над K верна IsAlgClosure для соответствующего подтипа.

LaTeX

$$$IsAlgClosure\; K\; (\text{AlgebraicClosure}(\text{Subtype} (\mathrm{instMembership}.mem E))).$$$

Lean4

instance [Algebra.IsAlgebraic K E] : IsAlgClosure K (AlgebraicClosure E) :=
  ⟨AlgebraicClosure.isAlgClosed E, Algebra.IsAlgebraic.trans K E (AlgebraicClosure E)⟩

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