English
The i-th coefficient of minpolyDiv satisfies a relation with the i+1 coefficient of minpoly via the base change X → x.
Русский
Для i-го коэффициента minpolyDiv существует зависимость через коэффициент minpoly на i+1 по замене X на x.
LaTeX
$$coeff (minpolyDiv R x) i = algebraMap R S (coeff (minpoly R x) (i+1)) + coeff (minpolyDiv R x) (i+1) * x$$
Lean4
theorem coeff_minpolyDiv (i) :
coeff (minpolyDiv R x) i = algebraMap R S (coeff (minpoly R x) (i + 1)) + coeff (minpolyDiv R x) (i + 1) * x := by
rw [← coeff_map, ← minpolyDiv_spec R x]; simp [mul_sub]