English
For any i, the i-th coefficient of minpolyDiv lies in the adjoin of R and {x}.
Русский
Для любого i-ого коэффициента minpolyDiv принадлежит адъюнкту R и {x}.
LaTeX
$$coeff (minpolyDiv R x) i ∈ Algebra.adjoin R { x }$$
Lean4
theorem coeff_minpolyDiv_mem_adjoin (x : S) (i) : coeff (minpolyDiv R x) i ∈ Algebra.adjoin R { x } :=
by
by_contra H
have : ∀ j, coeff (minpolyDiv R x) (i + j) ∉ Algebra.adjoin R { x } := by intro j;
induction j with
| zero => exact H
| succ j IH =>
intro H; apply IH
rw [coeff_minpolyDiv]
refine add_mem ?_ (mul_mem H (Algebra.self_mem_adjoin_singleton R x))
exact Subalgebra.algebraMap_mem _ _
apply this (natDegree (minpolyDiv R x) + 1)
rw [coeff_eq_zero_of_natDegree_lt]
· exact zero_mem _
· cutsat