English
The same additive compatibility holds for two fractional ring elements p and q: ofFractionRing(p+q) = ofFractionRing(p) + ofFractionRing(q).
Русский
Сохранение сложения для элементов дробной локализации: ofFractionRing(p+q) = ofFractionRing(p) + ofFractionRing(q).
LaTeX
$$$\forall p,q \in \mathrm{FractionRing}(K[X]),\; \operatorname{ofFractionRing}(p+q) = \operatorname{ofFractionRing}(p) + \operatorname{ofFractionRing}(q)$$$
Lean4
theorem ofFractionRing_add (p q : FractionRing K[X]) : ofFractionRing (p + q) = ofFractionRing p + ofFractionRing q :=
(add_def _ _).symm