English
For a field homomorphism f, the lift of relrank(A.comap f, B) equals the lift of relrank(A, B.map f).
Русский
Для отображения f подъём relrank(A.comap f, B) равен подъёму relrank(A, B.map f).
LaTeX
$$$ \operatorname{lift}(\operatorname{relrank}(A.comap f, B)) = \operatorname{lift}(\operatorname{relrank}(A, B.map f))$$$
Lean4
theorem lift_relrank_comap (f : L →+* E) (B : Subfield L) :
lift.{v} (relrank (A.comap f) B) = lift.{w} (relrank A (B.map f)) :=
(lift_relrank_map_map _ _ f).symm.trans <|
congr_arg lift <|
relrank_eq_of_inf_eq <| by rw [map_comap_eq, f.fieldRange_eq_map, inf_assoc, ← map_inf, top_inf_eq]