English
The comap of separable closure along an algebra homomorphism equals the separable closure of the domain.
Русский
Обратный образ разделимого замыкания по алгебраическому гомоморфизму равен разделимому замыканию области.
LaTeX
$$$(separableClosure F K).comap i = separableClosure F E$$$
Lean4
/-- If `i` is an `F`-algebra homomorphism from `E` to `K`, then `i x` is contained in
`separableClosure F K` if and only if `x` is contained in `separableClosure F E`. -/
theorem map_mem_separableClosure_iff (i : E →ₐ[F] K) {x : E} : i x ∈ separableClosure F K ↔ x ∈ separableClosure F E :=
by simp_rw [mem_separableClosure_iff, IsSeparable, minpoly.algHom_eq i i.injective]