English
Let ∠ p1 p2 p3 = π/2. Then dist(p1,p2) / sin(∠ p2 p3 p1) = dist(p1,p3).
Русский
Пусть ∠ p1 p2 p3 = π/2. Тогда dist(p1,p2) / sin(∠ p2 p3 p1) = dist(p1,p3).
LaTeX
$$$ \dfrac{\operatorname{dist}(p_1,p_2)}{\sin(\angle p_2 p_3 p_1)} = \operatorname{dist}(p_1,p_3) $$$
Lean4
/-- The cosine of an angle in a right-angled triangle multiplied by the hypotenuse equals the
adjacent side. -/
theorem cos_angle_mul_dist_of_angle_eq_pi_div_two {p₁ p₂ p₃ : P} (h : ∠ p₁ p₂ p₃ = π / 2) :
Real.cos (∠ p₂ p₃ p₁) * dist p₁ p₃ = dist p₃ p₂ :=
by
rw [angle, ← inner_eq_zero_iff_angle_eq_pi_div_two, real_inner_comm, ← neg_eq_zero, ← inner_neg_left,
neg_vsub_eq_vsub_rev] at h
rw [angle, dist_eq_norm_vsub' V p₃ p₂, dist_eq_norm_vsub V p₁ p₃, ← vsub_add_vsub_cancel p₁ p₂ p₃, add_comm,
cos_angle_add_mul_norm_of_inner_eq_zero h]