English
If R ≠ 0 and y ≠ c, inversion(c,R,x) ∈ perpBisector(c, inversion(c,R,y)) iff dist(x,y) = dist(y,c) and x ≠ c.
Русский
Если R ≠ 0 и y ≠ c, inversion(c,R,x) лежит на perpBisector(c, inversion(c,R,y)) тогда и только тогда, когда dist(x,y) = dist(y,c) и x ≠ c.
LaTeX
$$R ≠ 0 ∧ y ≠ c ⇒ (inversion(c,R,x) ∈ perpBisector(c, inversion(c,R,y)) ⇔ dist(x,y) = dist(y,c) ∧ x ≠ c)$$
Lean4
/-- The inversion with center `c` and radius `R` maps a sphere passing through the center to a
hyperplane. -/
theorem inversion_mem_perpBisector_inversion_iff' (hR : R ≠ 0) (hy : y ≠ c) :
inversion c R x ∈ perpBisector c (inversion c R y) ↔ dist x y = dist y c ∧ x ≠ c :=
by
rcases eq_or_ne x c with rfl | hx
· simp [*]
· simp [inversion_mem_perpBisector_inversion_iff hR hx hy, hx]