English
Equality of pullback bracket with bracket of pullbacks.
Русский
Равенство подвода скобки и скобки подвводов.
LaTeX
$$$\mathrm{mpullbackWithin}(I, I', f, \mathrm{mlieBracketWithin}(I', V, W, t), s, x_0) = \mathrm{mlieBracketWithin}(I, \mathrm{mpullbackWithin}(I, I', f, V, s), \mathrm{mpullbackWithin}(I, I', f, W, s), s, x_0)$$$
Lean4
theorem _root_.DifferentiableWithinAt.mlieBracketWithin_congr_mono
(hV : MDifferentiableWithinAt I I.tangent (fun x ↦ (V x : TangentBundle I M)) s x) (hVs : EqOn V₁ V t)
(hVx : V₁ x = V x) (hW : MDifferentiableWithinAt I I.tangent (fun x ↦ (W x : TangentBundle I M)) s x)
(hWs : EqOn W₁ W t) (hWx : W₁ x = W x) (hxt : UniqueMDiffWithinAt I t x) (h₁ : t ⊆ s) :
mlieBracketWithin I V₁ W₁ t x = mlieBracketWithin I V W s x :=
by
rw [mlieBracketWithin_congr hVs hVx hWs hWx]
exact mlieBracketWithin_subset h₁ hxt hV hW