English
If f is bijective, then Con.comap f H (conGen rel) equals conGen (λ x y, rel (f x) (f y)).
Русский
Если f биективна, то Con.comap f H (conGen rel) равняется conGen (λ x y, rel (f x) (f y)).
LaTeX
$$Con.comap f H (conGen rel) = conGen (fun x y ↦ rel (f x) (f y))$$
Lean4
@[to_additive]
theorem comap_conGen_of_bijective {M N : Type*} [Mul M] [Mul N] (f : M → N) (hf : Function.Bijective f)
(H : ∀ (x y : M), f (x * y) = f x * f y) (rel : N → N → Prop) :
Con.comap f H (conGen rel) = conGen (fun x y ↦ rel (f x) (f y)) :=
comap_conGen_equiv (MulEquiv.ofBijective (MulHom.mk f H) hf) rel