English
The Ore condition of a fraction: oreDenom(r,s) · r = oreNum(r,s) · s.
Русский
Условие Оре дроби: oreDenom(r,s) · r = oreNum(r,s) · s.
LaTeX
$$oreDenom(r,s) * r = oreNum(r,s) * s$$
Lean4
/-- The Ore condition of a fraction, expressed in terms of `oreNum` and `oreDenom`. -/
@[to_additive AddOreLocalization.add_ore_eq /--
The Ore condition of a difference, expressed in terms of `oreMin` and `oreSubtra`. -/
]
theorem ore_eq (r : R) (s : S) : oreDenom r s * r = oreNum r s * s :=
OreSet.ore_eq r s