English
For a finite affinely independent family, the vector span has dimension one less than its cardinality.
Русский
Для конечной аффинно независимой семьи размерность vectorSpan на единицу меньше ее мощности.
LaTeX
$$$\operatorname{finrank}_k\bigl(\operatorname{vectorSpan}_k(\operatorname{SetRange}(p))\bigr) + 1 = |\iota|$$$
Lean4
/-- The `vectorSpan` of a finite affinely independent family has
dimension one less than its cardinality. -/
theorem finrank_vectorSpan [Fintype ι] {p : ι → P} (hi : AffineIndependent k p) {n : ℕ} (hc : Fintype.card ι = n + 1) :
finrank k (vectorSpan k (Set.range p)) = n := by
classical
rw [← Finset.card_univ] at hc
rw [← Set.image_univ, ← Finset.coe_univ, ← Finset.coe_image]
exact hi.finrank_vectorSpan_image_finset hc