English
For every m in M, the image ι_Q(m) in the Clifford algebra squares to the scalar Q(m) when viewed in the base ring R via the algebra map.
Русский
Для каждого вектора m из M образ ι_Q(m) в клиффордовой алгебре имеет квадрат, равный скаляру Q(m), получаемому через алгебраическое отображение.
LaTeX
$$$\\iota_Q(m) \\cdot \\iota_Q(m) = \\mathrm{algebraMap}_{R \\to Clifford(Q)}(Q(m))$$$
Lean4
/-- As well as being linear, `ι Q` squares to the quadratic form -/
@[simp]
theorem ι_sq_scalar (m : M) : ι Q m * ι Q m = algebraMap R _ (Q m) :=
by
rw [ι]
erw [LinearMap.comp_apply]
rw [AlgHom.toLinearMap_apply, ← map_mul (RingQuot.mkAlgHom R (Rel Q)), RingQuot.mkAlgHom_rel R (Rel.of m),
AlgHom.commutes]
rfl