English
For W ⊆ M and f: N →_R M, the same inequality as before holds (mirror statement).
Русский
Для W ⊆ M и отображения f: N →_R M выполняется не хуже предыдущего неравенство.
LaTeX
$$theorem dualAnnihilator_map_dualMap_le {N : Type*} [AddCommMonoid N] [Module R N] (W : Submodule R M) (f : N →ₗ[R] M) :\n W.dualAnnihilator.map f.dualMap ≤ (W.comap f).dualAnnihilator := by ...$$
Lean4
theorem dualAnnihilator_map_dualMap_le {N : Type*} [AddCommMonoid N] [Module R N] (W : Submodule R M) (f : N →ₗ[R] M) :
W.dualAnnihilator.map f.dualMap ≤ (W.comap f).dualAnnihilator := by intro; aesop