English
If f and g commute and ker f is disjoint from ker g, then ker(f ∘ g) = ker f ⊔ ker g.
Русский
Если f и g commute и ker f дисjoint ker g, то ker(f ∘ g) = ker f ⊔ ker g.
LaTeX
$$$[\operatorname{FiniteDimensional}_K V] {f g: V \to V} (h: \operatorname{Commute} f g) (h': \operatorname{Disjoint}(\ker f)(\ker g)) : \ker(f \circ g) = \ker f \; \bigoplus\; \ker g$$$
Lean4
theorem ker_comp_eq_of_commute_of_disjoint_ker [FiniteDimensional K V] {f g : V →ₗ[K] V} (h : Commute f g)
(h' : Disjoint (ker f) (ker g)) : ker (f ∘ₗ g) = ker f ⊔ ker g :=
by
suffices ∀ x, f x = 0 → f (g x) = 0 by rw [ker_comp, comap_eq_sup_ker_of_disjoint _ h']; simpa
intro x hx
rw [← comp_apply, ← Module.End.mul_eq_comp, h.eq, Module.End.mul_apply, hx, map_zero]