English
Let s be a set with Nonempty s and Finite s, and lin_ind be LinearIndependent K ((↑) : s → V) with card_eq : s.toFinset.card = finrank K V. Then the coe of setBasisOfLinearIndependentOfCardEqFinrank equals the inclusion map from s to V.
Русский
Пусть s ненулево и конечно, линейно независимое отображение из s в V; тогда основание setBasisOfLinearIndependentOfCardEqFinrank коe совпадает с включением s в V.
LaTeX
$$$\\bigl(\\text{setBasisOfLinearIndependentOfCardEqFinrank } lin\\_ind card\\_eq\\bigr) = (\\uparrow) : s \\to V$.$$
Lean4
@[simp]
theorem coe_setBasisOfLinearIndependentOfCardEqFinrank {s : Set V} [Nonempty s] [Fintype s]
(lin_ind : LinearIndependent K ((↑) : s → V)) (card_eq : s.toFinset.card = finrank K V) :
⇑(setBasisOfLinearIndependentOfCardEqFinrank lin_ind card_eq) = ((↑) : s → V) := by
simp [setBasisOfLinearIndependentOfCardEqFinrank]