English
An additive isomorphism e between submodules yields a determinant whose natAbs equals the cardinality of the quotient M/N.
Русский
Канал令人:аддитивное изоморфизм e между подмодулями даёт детерминант, natAbs которого равен кардинальности модуля M/N.
LaTeX
$$$$ \operatorname{natAbs}( \det( N.subtype \circ e ) ) = \#( M / N ). $$$$
Lean4
theorem relIndex_eq_natAbs_det {E : Type*} [AddCommGroup E] (L₁ L₂ : AddSubgroup E) (H : L₁ ≤ L₂) {ι : Type*}
[DecidableEq ι] [Fintype ι] (b₁ : Basis ι ℤ L₁.toIntSubmodule) (b₂ : Basis ι ℤ L₂.toIntSubmodule) :
L₁.relIndex L₂ = (b₂.det (fun i ↦ ⟨b₁ i, (H (SetLike.coe_mem _))⟩)).natAbs :=
by
rw [relIndex, index_eq_natAbs_det b₂ _ (b₁.map (addSubgroupOfEquivOfLe H).toIntLinearEquiv.symm)]
rfl