English
A particular case of det_fromBlocks₂₂ when the bottom-right block is the identity; det equals det(A − B C).
Русский
Особый случай det_fromBlocks₂₂, когда D = I, даёт det(fromBlocks(A,B,C,I)) = det(A − B C).
LaTeX
$$$\\det\\mathrm{fromBlocks}(A,B,C,I) = \\det\\bigl(A - B C\\bigr)$$$
Lean4
@[simp]
theorem detp_neg_one_one : detp (-1) (1 : Matrix n n R) = 0 :=
by
rw [detp, sum_eq_zero]
intro σ hσ
have hσ1 : σ ≠ 1 := by
contrapose! hσ
rw [hσ, mem_ofSign, sign_one]
decide
obtain ⟨i, hi⟩ := not_forall.mp (mt Perm.ext_iff.mpr hσ1)
exact prod_eq_zero (mem_univ i) (one_apply_ne' hi)