English
For any i ≠ j, the i,j-entry of A·adjp 1 A equals the i,j-entry of A·adjp(-1) A; a refinement of the previous diagonal/result statements.
Русский
Для любых i ≠ j, элемент (i,j) в A·adjp(1)A совпадает с элементом (i,j) в A·adjp(-1)A.
LaTeX
$$$(A \\cdot \\operatorname{adjp}(1) A)_{ij} = (A \\cdot \\operatorname{adjp}(-1) A)_{ij} \\quad (i \\neq j)$$$
Lean4
theorem isAddUnit_mul (hAB : A * B = 1) (i j k : n) (hij : i ≠ j) : IsAddUnit (A i k * B k j) :=
by
revert k
rw [← IsAddUnit.sum_univ_iff, ← mul_apply, hAB, one_apply_ne hij]
exact isAddUnit_zero