English
Let s ⊆ α, t ⊆ β, u ⊆ γ. Then the preimage under the inverse associativity of (s × t) × u equals s × t × u.
Русский
Пусть s ⊆ α, t ⊆ β, u ⊆ γ. Тогда предобраз под действием обратной ассоциации от (s × t) × u равен s × t × u.
LaTeX
$$$ (\mathrm{Equiv.prodAssoc}\, \alpha \ beta \ gamma)^{-1} ( (s \times t) \times u ) = s \times t \times u $$$
Lean4
@[simp]
theorem prod_assoc_symm_preimage {α β γ} {s : Set α} {t : Set β} {u : Set γ} :
(Equiv.prodAssoc α β γ).symm ⁻¹' (s ×ˢ t) ×ˢ u = s ×ˢ t ×ˢ u :=
by
ext
simp [and_assoc]
-- `@[simp]` doesn't like these lemmas, as it uses `Set.image_congr'` to turn `Equiv.prodAssoc`
-- into a lambda expression and then unfold it.