English
If s ⊆ α is analytic and f: α → β is defined and continuous on s, then the image f''s is analytic.
Русский
Если s ⊆ α аналитично и f: α → β непрерывна на s, то образ f''s аналитичен.
LaTeX
$$$AnalyticSet(s) \rightarrow (f: \alpha \to \beta) \\text{ ContinuousOn } f\; s \Rightarrow \operatorname{AnalyticSet}(f'' s).$$$
Lean4
/-- The continuous image of an analytic set is analytic -/
theorem image_of_continuousOn {β : Type*} [TopologicalSpace β] {s : Set α} (hs : AnalyticSet s) {f : α → β}
(hf : ContinuousOn f s) : AnalyticSet (f '' s) :=
by
rcases analyticSet_iff_exists_polishSpace_range.1 hs with ⟨γ, γtop, γpolish, g, g_cont, gs⟩
have : f '' s = range (f ∘ g) := by rw [range_comp, gs]
rw [this]
apply analyticSet_range_of_polishSpace
apply hf.comp_continuous g_cont fun x => _
rw [← gs]
exact mem_range_self