English
If s ⊂ γ is closed, f is continuous on s and injective on s, then f''s is a measurable set.
Русский
Если s замкнуто в γ, функция f непрерывна на s и инъективна на s, то образ f''s измерим.
LaTeX
$$MeasurableSet (f '' s)$$
Lean4
theorem measurableSet_image_of_continuousOn_injOn [TopologicalSpace γ] [PolishSpace γ] {β : Type*} [TopologicalSpace β]
[T2Space β] [MeasurableSpace β] [OpensMeasurableSpace β] {s : Set γ} (hs : IsClosed s) {f : γ → β}
(f_cont : ContinuousOn f s) (f_inj : InjOn f s) : MeasurableSet (f '' s) :=
by
rw [image_eq_range]
haveI : PolishSpace s := IsClosed.polishSpace hs
apply measurableSet_range_of_continuous_injective
· rwa [continuousOn_iff_continuous_restrict] at f_cont
· rwa [injOn_iff_injective] at f_inj