English
For AEStronglyMeasurable g and AEMeasurable f, MemLp g on Measure.map f μ is equivalent to MemLp (g ∘ f) on μ.
Русский
Для AEStronglyMeasurable g и AEMeasurable f совместимо MemLp g на Measure.map f μ и MemLp (g ∘ f) на μ.
LaTeX
$$MemLp g p (Measure.map f μ) ↔ MemLp (g ∘ f) p μ$$
Lean4
theorem eLpNorm_map_measure (hg : AEStronglyMeasurable g (Measure.map f μ)) (hf : AEMeasurable f μ) :
eLpNorm g p (Measure.map f μ) = eLpNorm (g ∘ f) p μ :=
by
by_cases hp_zero : p = 0
· simp only [hp_zero, eLpNorm_exponent_zero]
by_cases hp_top : p = ∞
· simp_rw [hp_top, eLpNorm_exponent_top]
exact eLpNormEssSup_map_measure hg hf
simp_rw [eLpNorm_eq_lintegral_rpow_enorm hp_zero hp_top, lintegral_map' (hg.enorm.pow_const p.toReal) hf,
Function.comp_apply]