English
If the function is integrable, the L1-enorm of the difference between the range-based approxOn and f tends to zero.
Русский
Если функция интегрируема, то линегральная норма различия между аппроксимацией по диапазону и f сходится к нулю.
LaTeX
$$$Tendsto( n \\mapsto \\int \\! \\|approxOn f fmeas (range f \\cup \\{0\\}) 0 (by simp) n x - f x\\| dx )_{n\\to\\infty} = 0.$$$
Lean4
theorem tendsto_approxOn_range_L1_enorm [OpensMeasurableSpace E] {f : β → E} {μ : Measure β}
[SeparableSpace (range f ∪ {0} : Set E)] (fmeas : Measurable f) (hf : Integrable f μ) :
Tendsto (fun n => ∫⁻ x, ‖approxOn f fmeas (range f ∪ {0}) 0 (by simp) n x - f x‖ₑ ∂μ) atTop (𝓝 0) :=
by
apply tendsto_approxOn_L1_enorm fmeas
· filter_upwards with x using subset_closure (by simp)
· simpa using hf.2