English
If s is measurable and f=g a.e. on s, then laverage over μ restricted to s is the same for f and g.
Русский
Если s измеримо и f=g почти пожалуй на s, то laverage по μ|s одинакова для f и g.
LaTeX
$$$hs: MeasurableSet s\\Rightarrow (f=g\\text{ a.e. on } s) \\Rightarrow laverage_{μ|s}(f) = laverage_{μ|s}(g)$$$
Lean4
theorem laverage_union (hd : AEDisjoint μ s t) (ht : NullMeasurableSet t μ) :
⨍⁻ x in s ∪ t, f x ∂μ = μ s / (μ s + μ t) * ⨍⁻ x in s, f x ∂μ + μ t / (μ s + μ t) * ⨍⁻ x in t, f x ∂μ := by
rw [restrict_union₀ hd ht, laverage_add_measure, restrict_apply_univ, restrict_apply_univ]