English
The integral of the laverage over μ equals the integral of f over μ (Lintegral vs laverage).
Русский
Интеграл от laverage по μ равен интегралу f по μ.
LaTeX
$$$\\int f\\, d\\mu = \\int⁻ f\\, d\\mu$$$
Lean4
theorem laverage_union_mem_openSegment (hd : AEDisjoint μ s t) (ht : NullMeasurableSet t μ) (hs₀ : μ s ≠ 0)
(ht₀ : μ t ≠ 0) (hsμ : μ s ≠ ∞) (htμ : μ t ≠ ∞) :
⨍⁻ x in s ∪ t, f x ∂μ ∈ openSegment ℝ≥0∞ (⨍⁻ x in s, f x ∂μ) (⨍⁻ x in t, f x ∂μ) :=
by
refine
⟨μ s / (μ s + μ t), μ t / (μ s + μ t), ENNReal.div_pos hs₀ <| add_ne_top.2 ⟨hsμ, htμ⟩,
ENNReal.div_pos ht₀ <| add_ne_top.2 ⟨hsμ, htμ⟩, ?_, (laverage_union hd ht).symm⟩
rw [← ENNReal.add_div, ENNReal.div_self (add_eq_zero.not.2 fun h => hs₀ h.1) (add_ne_top.2 ⟨hsμ, htμ⟩)]