English
If f is measure-preserving and a measurable embedding, then ∫_{f''s} g ≤ ∫_{s} g∘f with g: Y → E.
Русский
Если f сохраняет меру и измеримо вложение, то интеграл по образу f''s ≤ интегралу по s от g∘f.
LaTeX
$$$$ \\int_{y \\in f''s} g(y) \\, d\\nu(y) = \\int_{x \\in s} g(f(x)) \\, d\\mu(x) $$$$
Lean4
theorem setIntegral_trim {X} {m m0 : MeasurableSpace X} {μ : Measure X} (hm : m ≤ m0) {f : X → E}
(hf_meas : StronglyMeasurable[m] f) {s : Set X} (hs : MeasurableSet[m] s) :
∫ x in s, f x ∂μ = ∫ x in s, f x ∂μ.trim hm := by rwa [integral_trim hm hf_meas, restrict_trim hm μ]