English
The circle integral can be computed by integrating over θ in the closed interval Icc[0, 2π] using the same integrand deriv(circleMap c R) θ • f(circleMap c R θ).
Русский
Круговой интеграл можно вычислять, интегрируя по θ на отрезке Icc[0,2π] той же интеграндной функции deriv(circleMap c R) θ • f(circleMap c R θ).
LaTeX
$$$\\oint z\\in C(c,R) f(z)\\;dz = \\int_{\\theta\\in Icc\\;0\\;2\\pi} deriv(circleMap\\; c\\; R)\\;\\theta \\;\\cdot f(circleMap\\; c\\; R\\; \\theta) \\, d\\theta$$$
Lean4
/-- `∮ z in C(c, R), f z` is the circle integral $\oint_{|z-c|=R} f(z)\,dz$. -/
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