English
If hφ is an ae-cover, f is AEStronglyMeasurable, and the Tendsto of the norms of f over φ i is to I, then f is integrable.
Русский
Если ae-покрытие hφ и f — AEStronglyMeasurable, и предел нормы ‖f‖ над φ(i) существует, то f интегрируем.
LaTeX
$$$\\forall hφ, (AEStronglyMeasurable f μ) \\Rightarrow Tendsto (\\lambda i, ∥f∥) l (\\mathcal{N} I) \\Rightarrow Integrable f μ$$$
Lean4
theorem integrable_of_lintegral_enorm_tendsto [l.NeBot] [l.IsCountablyGenerated] {φ : ι → Set α} (hφ : AECover μ l φ)
{f : α → E} (I : ℝ) (hfm : AEStronglyMeasurable f μ)
(htendsto : Tendsto (fun i => ∫⁻ x in φ i, ‖f x‖ₑ ∂μ) l (𝓝 <| .ofReal I)) : Integrable f μ :=
by
refine hφ.integrable_of_lintegral_enorm_bounded (max 1 (I + 1)) hfm ?_
refine htendsto.eventually (ge_mem_nhds ?_)
refine (ENNReal.ofReal_lt_ofReal_iff (lt_max_of_lt_left zero_lt_one)).2 ?_
exact lt_max_of_lt_right (lt_add_one I)