English
If t is countable and the sets s i are null-measurable with respect to μ, then the lintegral over the biUnion equals the sum over i of the integrals over s_i.
Русский
Если t счётно, а множества s_i нуль - measurables по μ, тогда линеграл по объединению по i в t равен сумме интегралов по s_i.
LaTeX
$$$$ \\int^- a in \\bigcup_{i \\in t} s_i, f(a) \\, d\\mu = \\sum_{i \\in t} \\int^- a in s_i, f(a) \\, d\\mu. $$$$
Lean4
theorem lintegral_biUnion₀ {t : Set β} {s : β → Set α} (ht : t.Countable) (hm : ∀ i ∈ t, NullMeasurableSet (s i) μ)
(hd : t.Pairwise (AEDisjoint μ on s)) (f : α → ℝ≥0∞) :
∫⁻ a in ⋃ i ∈ t, s i, f a ∂μ = ∑' i : t, ∫⁻ a in s i, f a ∂μ :=
by
haveI := ht.toEncodable
rw [biUnion_eq_iUnion, lintegral_iUnion₀ (SetCoe.forall'.1 hm) (hd.subtype _ _)]