English
The comap of the complement operation along a measurable function equals the comap of the function itself (Boolean algebra setting).
Русский
Comap операции дополнения вдоль измеримой функции равен comap самой функции (в контексте буловой алгебры).
LaTeX
$$$\\mathrm{MeasurableSpace.comap}\\ \\big(\\lambda a. (f(a))^{\\complement}\\big) = \\mathrm{MeasurableSpace.comap} f$$$
Lean4
theorem comap_compl {m' : MeasurableSpace β} [BooleanAlgebra β] (h : Measurable (compl : β → β)) (f : α → β) :
MeasurableSpace.comap (fun a => (f a)ᶜ) inferInstance = MeasurableSpace.comap f inferInstance :=
by
rw [← Function.comp_def, ← MeasurableSpace.comap_comp]
congr
exact (MeasurableEquiv.ofInvolutive _ compl_involutive h).measurableEmbedding.comap_eq