English
If K1 ⊆ K2 then chaar(K0, K1) ≤ chaar(K0, K2).
Русский
Если K1 ⊆ K2, то chaar(K0, K1) ≤ chaar(K0, K2).
LaTeX
$$$\text{chaar}(K_0, K_1) \le \text{chaar}(K_0, K_2)\quad(K_1 \subseteq K_2)$$$
Lean4
@[to_additive addCHaar_self]
theorem chaar_self (K₀ : PositiveCompacts G) : chaar K₀ K₀.toCompacts = 1 :=
by
let eval : (Compacts G → ℝ) → ℝ := fun f => f K₀.toCompacts
have : Continuous eval := continuous_apply _
change chaar K₀ ∈ eval ⁻¹' {(1 : ℝ)}
apply mem_of_subset_of_mem _ (chaar_mem_clPrehaar K₀ ⊤)
unfold clPrehaar; rw [IsClosed.closure_subset_iff]
· rintro _ ⟨U, ⟨_, h2U, h3U⟩, rfl⟩; apply prehaar_self
rw [h2U.interior_eq]; exact ⟨1, h3U⟩
· apply continuous_iff_isClosed.mp this; exact isClosed_singleton