English
For ψ : K ⟶ L.extend e and i,i' with h : e.f i = i', the equality (e.homRestrict ψ).f i = (K.restrictionXIso e h).hom ≫ ψ.f i' ≫ (L.extendXIso e h).hom holds.
Русский
Для ψ: K ⟶ L.extend e и i, i' с h: e.f i = i', верно равенство (e.homRestrict ψ).f i = (K.restrictionXIso e h).hom ≫ ψ.f i' ≫ (L.extendXIso e h).hom.
LaTeX
$$$$ (e.homRestrict ψ).f i = (K.restrictionXIso e h).hom \circ ψ.f i' \circ (L.extendXIso e h).hom $$$$
Lean4
instance map_isStrictlySupported [K.IsStrictlySupported e] : ((F.mapHomologicalComplex c').obj K).IsStrictlySupported e
where
isZero i'
hi' := by
rw [IsZero.iff_id_eq_zero]
dsimp
rw [← F.map_id, (K.isZero_X_of_isStrictlySupported e i' hi').eq_of_src (𝟙 _) 0, F.map_zero]