English
If E is measurable and the limsup of the measures of E under the sequence is bounded above by μ(E), then the liminf of the measures of E's complement is bounded above by μ(Eᶜ).
Русский
Пусть E измеримо. Если верхняя граница по лимит-сукупностям мер E над последовательностью не превосходит μ(E), то верхняя граница по лимит-нижним мерам комплемента E не превосходит μ(Еᶜ).
LaTeX
$$$\text{Measurable}(E) \land \Bigl( \limsup_i \mu_i(E) \le \mu(E) \Bigr) \Rightarrow \mu(E^c) \le \liminf_i \mu_i(E^c)$$$
Lean4
theorem le_measure_compl_liminf_of_limsup_measure_le {ι : Type*} {L : Filter ι} {μ : Measure Ω} {μs : ι → Measure Ω}
[IsProbabilityMeasure μ] [∀ i, IsProbabilityMeasure (μs i)] {E : Set Ω} (E_mble : MeasurableSet E)
(h : (L.limsup fun i ↦ μs i E) ≤ μ E) : μ Eᶜ ≤ L.liminf fun i ↦ μs i Eᶜ :=
by
rcases L.eq_or_neBot with rfl | hne
· simp only [liminf_bot, le_top]
have meas_Ec : μ Eᶜ = 1 - μ E := by simpa only [measure_univ] using measure_compl E_mble (measure_lt_top μ E).ne
have meas_i_Ec : ∀ i, μs i Eᶜ = 1 - μs i E := by
intro i
simpa only [measure_univ] using measure_compl E_mble (measure_lt_top (μs i) E).ne
simp_rw [meas_Ec, meas_i_Ec]
rw [show (L.liminf fun i : ι ↦ 1 - μs i E) = L.liminf ((fun x ↦ 1 - x) ∘ fun i : ι ↦ μs i E) from rfl]
have key :=
antitone_const_tsub.map_limsup_of_continuousAt (F := L) (fun i ↦ μs i E)
(ENNReal.continuous_sub_left ENNReal.one_ne_top).continuousAt
simpa [← key] using antitone_const_tsub h