English
If s1 and s2 are Carathéodory-measurable with respect to m, then s1 ∪ s2 is Carathéodory-measurable.
Русский
Если s1 и s2 карatheodory-измеримы относительно m, то s1 ∪ s2 тоже карatheodory-измеримо.
LaTeX
$$m.IsCaratheodory s1 \rightarrow m.IsCaratheodory s2 \rightarrow m.IsCaratheodory (s1 \cup s2)$$
Lean4
theorem isCaratheodory_union (h₁ : IsCaratheodory m s₁) (h₂ : IsCaratheodory m s₂) : IsCaratheodory m (s₁ ∪ s₂) :=
fun t =>
by
rw [h₁ t, h₂ (t ∩ s₁), h₂ (t \ s₁), h₁ (t ∩ (s₁ ∪ s₂)), inter_diff_assoc _ _ s₁, Set.inter_assoc _ _ s₁,
inter_eq_self_of_subset_right Set.subset_union_left, union_diff_left, h₂ (t ∩ s₁)]
simp [diff_eq, add_assoc]