English
If every member s of g is measurable, then any t in generatePiSystem(g) is measurable with respect to generateFrom g.
Русский
Если каждый элемент s из g измерим, то любой t из generatePiSystem(g) измерим в generateFrom g.
LaTeX
$$$$ \forall s \in g,\ MeasurableSet(s) \implies (t \in \mathrm{generatePiSystem}(g)\Rightarrow \ MeasurableSet_{generateFrom(g)}(t)) $$$$
Lean4
theorem generatePiSystem_measurableSet [M : MeasurableSpace α] {S : Set (Set α)} (h_meas_S : ∀ s ∈ S, MeasurableSet s)
(t : Set α) (h_in_pi : t ∈ generatePiSystem S) : MeasurableSet t := by
induction h_in_pi with
| base h_s => apply h_meas_S _ h_s
| inter _ _ _ h_s h_u => apply MeasurableSet.inter h_s h_u