English
Given μ, s, t with a Lebesgue decomposition for t relative to μ, if hadd expresses s = t + μ.withDensityᵥ f with f measurable, then s has Lebesgue decomposition with respect to μ.
Русский
Пусть μ, s, t имеют разложение Лебега, и если s = t + μ.withDensityᵥ f при измеримой f, то s имеет разложение Лебега относительно μ.
LaTeX
$$$[s.HaveLebesgueDecomposition μ] \Rightarrow \text{eq}(s, t + μ.withDensityᵥ f) \Rightarrow s.HaveLebesgueDecomposition μ$$$
Lean4
theorem haveLebesgueDecomposition_mk (μ : Measure α) {f : α → ℝ} (hf : Measurable f)
(htμ : t ⟂ᵥ μ.toENNRealVectorMeasure) (hadd : s = t + μ.withDensityᵥ f) : s.HaveLebesgueDecomposition μ :=
by
by_cases hfi : Integrable f μ
· exact haveLebesgueDecomposition_mk' μ hf hfi htμ hadd
· rw [withDensityᵥ, dif_neg hfi, add_zero] at hadd
refine haveLebesgueDecomposition_mk' μ measurable_zero (integrable_zero _ _ μ) htμ ?_
rwa [withDensityᵥ_zero, add_zero]