English
Same determinant identity as before, expressed in an alternate form.
Русский
Та же тождество по(det) для fderiv_expMapBasis, выраженное иным способом.
LaTeX
$$$|(fderiv\_expMapBasis K x).\det| = \dots$$$
Lean4
theorem abs_det_fderiv_expMapBasis (x : realSpace K) :
|(fderiv_expMapBasis K x).det| =
Real.exp (x w₀ * Module.finrank ℚ K) * (∏ w : { w // IsComplex w }, expMapBasis x w.1)⁻¹ *
2⁻¹ ^ nrComplexPlaces K *
(Module.finrank ℚ K) *
regulator K :=
by
simp_rw [fderiv_expMapBasis, det, coe_comp, LinearMap.det_comp, fderiv_expMap, coe_pi, coe_comp, coe_proj,
LinearMap.det_pi, LinearMap.det_ring, ContinuousLinearMap.coe_coe, smulRight_apply, one_apply, one_smul, abs_mul,
abs_det_completeBasis_equivFunL_symm, prod_deriv_expMap_single]
simp_rw [abs_mul, Real.exp_mul, abs_pow, Real.rpow_natCast, abs_of_nonneg (Real.exp_nonneg _), abs_inv, abs_prod,
abs_of_nonneg (expMapBasis_nonneg _ _), Nat.abs_ofNat]
ring