English
If s and t have upper bounds and f is monotone in the second argument and antitone in the first argument, then image2 f s t is bounded below; i.e., there exists a lower bound for image2 f s t.
Русский
Если s и t ограничены сверху, а f(·,·) монотонна по второму аргументу и антимонотонна по первому, то image2 f s t ограничено снизу.
LaTeX
$$BddAbove s → BddAbove t → BddBelow (Set.image2 f s t)$$
Lean4
theorem image2_bddBelow : BddAbove s → BddAbove t → BddBelow (Set.image2 f s t) :=
by
rintro ⟨a, ha⟩ ⟨b, hb⟩
exact ⟨f a b, mem_lowerBounds_image2_of_mem_upperBounds h₀ h₁ ha hb⟩