English
In a ring with a strict order, if a^n ≥ 0 eventually for all large n, then a ≥ 0.
Русский
В кольце с жёстким упорядочением, если a^n becomes nonnegative eventually, то a ≥ 0.
LaTeX
$$$\\forall \\alpha [\\text{Ring } \\alpha] [\\text{LinearOrder } \\alpha] [\\text{IsStrictOrderedRing } \\alpha],\\; (\\forall^{\\infty} n \\in \\operatorname{atTop}, 0 \\le a^{n}) \\Rightarrow 0 \\le a$$$
Lean4
theorem nonneg_of_eventually_pow_nonneg {α : Type*} [Ring α] [LinearOrder α] [IsStrictOrderedRing α] {a : α}
(h : ∀ᶠ n in atTop, 0 ≤ a ^ (n : ℕ)) : 0 ≤ a :=
let ⟨_n, ho, hn⟩ := (Nat.frequently_odd.and_eventually h).exists
ho.pow_nonneg_iff.1 hn