English
Supremum (least upper bound) of two CountableInterFilters l1 and l2 is CountableInterFilter (l1 ⊔ l2).
Русский
Супремум двух CountableInterFilter даёт CountableInterFilter для l1 ⊔ l2.
LaTeX
$$$\\text{countableInterFilter_sup}(l_1, l_2) : CountableInterFilter (l_1 \\ ⊔ \\ l_2)$$$
Lean4
/-- Supremum of two `CountableInterFilter`s is a `CountableInterFilter`. -/
instance countableInterFilter_sup (l₁ l₂ : Filter α) [CountableInterFilter l₁] [CountableInterFilter l₂] :
CountableInterFilter (l₁ ⊔ l₂) :=
by
refine ⟨fun S hSc hS => ⟨?_, ?_⟩⟩ <;> refine (countable_sInter_mem hSc).2 fun s hs => ?_
exacts [(hS s hs).1, (hS s hs).2]