English
For a surjective map m, disjointness of comaps is equivalent to disjointness of the original filters.
Русский
Для сюръективного отображения m дизjointность отображений через m эквивалентна дизjointности исходных фильтров.
LaTeX
$$$\\mathrm{Disjoint}(\\operatorname{comap} m\, g_1, \\operatorname{comap} m\, g_2) \\iff \\mathrm{Disjoint}(g_1,g_2)$$$
Lean4
theorem disjoint_comap_iff (h : Surjective m) : Disjoint (comap m g₁) (comap m g₂) ↔ Disjoint g₁ g₂ := by
rw [disjoint_iff, disjoint_iff, ← comap_inf, comap_surjective_eq_bot h]