English
(map m) ofComapInfPrincipal h equals g.
Русский
(map m)(ofComapInfPrincipal h) равно g.
LaTeX
$$$(\\mathrm{map}\\ m)(\\mathrm{ofComapInfPrincipal}\\ h) = g$$$
Lean4
theorem ofComapInfPrincipal_eq_of_map (h : m '' s ∈ g) : (ofComapInfPrincipal h).map m = g :=
by
let f := Filter.comap m g ⊓ 𝓟 s
haveI : f.NeBot := comap_inf_principal_neBot_of_image_mem h
apply eq_of_le
calc
Filter.map m (of f) ≤ Filter.map m f := map_mono (of_le _)
_ ≤ (Filter.map m <| Filter.comap m g) ⊓ Filter.map m (𝓟 s) := map_inf_le
_ = (Filter.map m <| Filter.comap m g) ⊓ (𝓟 <| m '' s) := by rw [map_principal]
_ ≤ ↑g ⊓ (𝓟 <| m '' s) := (inf_le_inf_right _ map_comap_le)
_ = ↑g := inf_of_le_left (le_principal_iff.mpr h)