English
If g is injective, then g ∘ f1 = g ∘ f2 implies f1 = f2; i.e., left-cancellation for pre-composition.
Русский
Если g инъективно, то g ∘ f1 = g ∘ f2 следует f1 = f2; левая отмена по композиции.
LaTeX
$$$\text{Injective } g \Rightarrow (g \circ f_1 = g \circ f_2 \;\text{ implies }\; f_1 = f_2)$$$
Lean4
@[simp]
theorem cancel_left {g : BoundedOrderHom β γ} {f₁ f₂ : BoundedOrderHom α β} (hg : Injective g) :
g.comp f₁ = g.comp f₂ ↔ f₁ = f₂ :=
⟨fun h => BoundedOrderHom.ext fun a => hg <| by rw [← BoundedOrderHom.comp_apply, h, BoundedOrderHom.comp_apply],
congr_arg _⟩